Problema Solution
Find the value of x such that (x,-3), (2,6) are apart of the graph of a line with a slope of 3/2
Answer provided by our tutors
the slope of a line that goes trough points (x1, y1) and (x2, y2) is
m = (y2 - y1)/(x2 - x1)
in our case
m = (6 - (-3))/(2 - x)
(6 - (-3))/(2 - x) = 3/2
by solving we find
x = -4
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