Problema Solution
write an equation of he line that goes through the points (1/2,1/3) and (-5/2,-2/3).
Answer provided by our tutors
the equation of the line trough points (x1, y1) and (x2, y2) is
y - y1 = m(x - x1)
where the slope m = change y/change in x
in our case we have
m = (1/3-(-2/3))/(1/2 - (-5/2))
m = 1/3
y - 1/2 = (1/3)(x - 1/3)
y = 1/2 + (1/3)x - 1/9
y = (1/3)x + 7/18