Problema Solution
An object is projected into the air with a vertical velocity of 24 feet per second. At what times will the object be on the ground? (it is on the ground when h is 0.)
Answer provided by our tutors
v0 = 24 ft/s initial velocity
a0 = - 32 ft/s^2 acceleration due to gravity
t = time, t>0
h = height
h = (1/2)a*t^2 + v0*t
h = - (1/2)32*t^2 + 24*t
h = - 16*t^2 + 24*t
it is on the ground when h = 0 thus
- 16*t^2 + 24*t = 0
by solving we find
t = 1.5 s
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the object will hit the ground after 1.5 seconds.