Problema Solution
the diagonal of a reciting;e is 9 meters longer that the width. The length is 21 meters. find the width of the rectangle
Answer provided by our tutors
let
l = 21 m the length of the rectangle
w = the width of the rectangle, w>0
d = the diagonal of the rectangle
the diagonal of a rectangle is 9 meters longer that the width
d = 9 + w
using the Pythagorean Theorem we can write
d^2 = l^2 + w^2
plug d = 9 + w and l = 21 into the last equation
(9 + w)^2 = 21^2 + w^2
by solving the equation we find
w = 20 m
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the width of the rectangle is 20 meters.