Problema Solution
A chemist needs to mix 15L of 10% acid solution with some 60% acid solution to get a mixture that 20 % acid. How many liters of the 60% solution should be used ?
Answer provided by our tutors
let
x = L of 60% acid solution needed for the mix
x + 15 liters is the total amount of the 20% mix
0.10*15 + 0.60*x = 0.20*(x + 15)
by solving we find
x = 3.75 L
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3.75L of the 60% solution should be used.