Problema Solution
write the equation of the line in slope intercept form that contains the points (1,6) and (6,-3)"
Answer provided by our tutors
the straight-line equations in the "slope-intercept" form is
y = mx + b
where "m" is the slope and "b" gives the y-intercept
m = (6 - (-3))/(1 - 6)
m = -9/5
y = (-9/5)x + b
the line goes trough (1,6) thus for x = 1
y = 6
(-9/5)*1 + b = 6
by solving we find
b = 7.8
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the equation of the line in slope intercept form is
y = (-9/5)x + 7.8