Problema Solution

two years ago a mom was 7 times as old as her daughter but in three years she would be four times as old as the girl. how old are they now

Answer provided by our tutors

let


m = the age of mom now

d = the age of daughter now


two years ago a mom was 7 times as old as her daughter


m - 2 = 7(d - 2)


in three years she would be four times as old as the girl


m + 3 = 4(d + 3)


by solving the system of equations


m - 2 = 7(d - 2)

m + 3 = 4(d + 3)


we find


m = 37 years


d = 7 years


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the mother is 37 years old now.

the daughter is 7 years old now.