Problema Solution
How many liters of a 20% alcohol solution should Mar mix with 50 liters of a 60% alcohol solution to obtain a 30% solution?
Answer provided by our tutors
let
x = the liters of the 20% alcohol solution needed for the mix
0.20x + 0.60*60 = 0.30(x + 60)
by solving we find
x = 150 L
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150 liters of the 20% alcohol solution should be used for the mix.