Problema Solution
The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 square feet. Draw the graph of the function A(w) that represents this problem. Determine the maxima or minima.
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
the length of a rectangle is 2 feet longer than the width
l = w + 2
the area of the rectangle A = l*w
plug l = w + 2 into A = l*w we get A(w) = (w + 2)w
click here to see the graph of A(w)
since l>=0 and w>=0 the minimum is A = 0 for l =0 and w = 0
the area of the rectangle is 8 square feet thus we have
(w + 2)w = 8
by solving we find
w = 2 ft
l = 2 + 2
l = 4 ft
click here to see the step by step solution of the quadratic equation
of the area of the rectangle is 8 ft^2 the width is 2 feet and the length is 4 feet.