Problema Solution
1 ml of a saline solution was mixed with 4 ml of pure water to make a 18% saline solution. Find the percent concentration of the first solution.
Answer provided by our tutors
let
p = percent concentration of the first solution
(p/100)*1 + 0*4 = 0.18(1 + 4)
by solving we find
p = 90%
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the percent concentration of the first solution is 90%.