Problema Solution
Divide the sum of (Y+4)^2 and (y+4)(y-4) by 2y
Answer provided by our tutors
((y+4)^2 + (y+4)(y-4)) / 2y = (y + 4)*(2y)/(2y) = y + 4
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Divide the sum of (Y+4)^2 and (y+4)(y-4) by 2y
((y+4)^2 + (y+4)(y-4)) / 2y = (y + 4)*(2y)/(2y) = y + 4
click here to see the step by step solution