Problema Solution
A private airplane leave an airport and flies due south at 192 mph. Two hours later, a jet leaves the same airport and flies due south at 960 mph. When will the jet overtake the plane?
Answer provided by our tutors
let
v1 = 192 mph the rate of plane
t1 = the time of travel of the plane
v2 = 960 mph the rate of the jet
t2 = the time of travel of the jet
2 hours later, a jet leaves the same airport and flies due south
t1 = t2 + 2
since speed = distance/time => distance = speed*time
v1*t1 = v2*t2
192*t1 = 960*t2 divide both sides by 192
t1 = 5*t2
by solving the system of equations
t1 = t2 + 2
t1 = 5*t2
we find
t1 = 2.5 h
t2 = 0.5 h
click here to see the step by step solution of the system of equations
the jet will overtake the plane half an hour after it leaves the airport.