Problema Solution

During a chemical reaction, the temperature

in the beaker decreased by 2°C every minute until 10:23 A.M. If the

temperature was 17°C at 10:00 A.M., when the reaction began, what was the

temperature at 10:23 A.M.?

Answer provided by our tutors

During a chemical reaction, the temperature

in the beaker decreased by 2°C every minute until 10:23 A.M. If the

temperature was 17°C at 10:00 A.M., when the reaction began, what was the

temperature at 10:23 A.M.?

Solution:

10:23 A.M. - 10:00 A.M. = 23 minutes

And the temperature decreased by 2°C every minute

So the temperature at 10:23 A.M.

= 17°C - 23* 2°C

= 17°C - 46°C

= -29°C

The temperature at 10:23 A.M.is -29°C