Problema Solution
During a chemical reaction, the temperature
in the beaker decreased by 2°C every minute until 10:23 A.M. If the
temperature was 17°C at 10:00 A.M., when the reaction began, what was the
temperature at 10:23 A.M.?
Answer provided by our tutors
During a chemical reaction, the temperature
in the beaker decreased by 2°C every minute until 10:23 A.M. If the
temperature was 17°C at 10:00 A.M., when the reaction began, what was the
temperature at 10:23 A.M.?
Solution:
10:23 A.M. - 10:00 A.M. = 23 minutes
And the temperature decreased by 2°C every minute
So the temperature at 10:23 A.M.
= 17°C - 23* 2°C
= 17°C - 46°C
= -29°C
The temperature at 10:23 A.M.is -29°C