Problema Solution
in the chemistry lab, a 30% and 80% alcohol are mixed to obtain 100 liters of a 50% alcohol solution. how many liters of the 30% solution were used?
Answer provided by our tutors
let
x = liters of the 30% alcohol solution used
y = liters of the 80% alcohol solution used
30% and 80% alcohol are mixed to obtain 100 liters of a 50% alcohol solution
x + y = 100
0.30*x + 0.80*y = 0.50*100
by solving the above system we find
x = 60 L
y = 40 L
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60 liters of the 30% solution are used.