Problema Solution
The half-life of the radioactive element krypton-91 is 10 seconds. If 16 grams of krypton-91 are initially present, how grams are present after 10 seconds? 20 seconds? 30 seconds? 40 seconds? 50 seconds?
Answer provided by our tutors
f(0) = 16
f(10) = f(0)/2 = 8
f(20) = f(10)/2 = 4
f(30) = f(20)/2 = 2
f(40) = f(30)/2 = 1
f(50) = f(0)/2 = 0.5