Problema Solution

The perimeter of a rectangle is 64cm. The length is 4cm less than twice the width. Find the length &width.

Answer provided by our tutors

let


l = the length of the rectangle

w = the width of the rectangle


the perimeter of a rectangle is 64 cm


2(l + w) = 64 divide both sides by 2


l + w = 32


the length is 4 cm less than twice the width


l = 2w - 4


by solving the system of equations


l + w = 32

l = 2w - 4


we find


l = 20 cm


w = 12 cm


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the length is 20 cm and the width is 12 cm.