Problema Solution
a boy has $9.50 saved from allowances. he has twice as many dimes as quarters and half as many nickels as quarters how many of each coin does he have
Answer provided by our tutors
1 nickle = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
let
n = the number of nickels
d = the number of dimes
q = the number of quarters
a boy has $9.50 = 950 cents saved from allowances
5n + 10d + 25q = 950
he has twice as many dimes as quarters
d = 2q
and half as many nickels as quarters
n = q/2
by solving the system of equations
5n + 10d + 25q = 950
d = 2q
n = q/2
we find
n = 10 nickles
d = 40 dimes
q = 20 quarters
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