Problema Solution
find two consecutive integers that the sum of twice the largest and 3 times the smallest is 57.
Answer provided by our tutors
the two consecutive integers can be written as
x and x+1, where x is integer
the sum of twice the largest and 3 times the smallest is 57
2(x + 1) + 3x = 57
by solving we find
x = 11
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11 + 1 = 12
the two consecutive integers are 11 and 12.