Problema Solution
If a ball is tossed into the air from a height of 18ft with a velocity of 32 ft per second, the altitude at the time (t) in seconds, Can be described by the function: A(t)=16t^2 +32t +18. Find the altitude of the ball at 2 seconds
Answer provided by our tutors
A(t) = 16t^2 +32t +18
we need to find the altitude of the ball at 2 seconds meaning we need to find A(t) when t = 2 s
A(2) = 16*2^2 + 32*2 + 18
A(2) = 16*4 + 64 + 18
A(2) = 146 ft
the altitude of the ball at 2 seconds is 146 ft.