Problema Solution

z varies directly with x^2 and inversely with y. When x=2 and y=4, z=3. What is the value of z when x=4 and y=9

Answer provided by our tutors

z varies directly with x^2 and inversely with y


z = k*(x^2/y)


where k is constant


When x=2 and y=4, z=3


3 = k *(2^2/4)


k(4/4) = 3


k = 3


z = (2x^2)/y


when x=4 and y=9 we have


z = (2*4^2)/9


z = (2*16)/9


z = 32/9


z = 3 5/9


z = 3,56