Problema Solution
z varies directly with x^2 and inversely with y. When x=2 and y=4, z=3. What is the value of z when x=4 and y=9
Answer provided by our tutors
z varies directly with x^2 and inversely with y
z = k*(x^2/y)
where k is constant
When x=2 and y=4, z=3
3 = k *(2^2/4)
k(4/4) = 3
k = 3
z = (2x^2)/y
when x=4 and y=9 we have
z = (2*4^2)/9
z = (2*16)/9
z = 32/9
z = 3 5/9
z = 3,56