Problema Solution

Find the smallest of three consecutive positive even integers such that the product of the two smaller integers is 28 more than twice the largest.

Answer provided by our tutors

let the three consecutive even positive integers can be written as


2x -2, 2x and 2x + 2


where x is integer and 2x - 2 < 2x < 2x + 2


the product of the two smaller integers is 28 more than twice the largest


(2x - 2)2x = 28 + 2(2x + 2)


by solving we find


x = 4


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2*4 - 2 = 6


2*4 = 8


2*4 + 2 = 10


the three consecutive positive even integers are 6, 8 and 10.