Problema Solution
Bob is planning to invest up to $25000 in city bank or state bank. he wants to invest at least 3000 dollars n city bank, but not more than 23000 dollars;since state bank does not insure more than 7000 dollars, he wants to invest no more than this amount in state bank. the interest at city bank is 7percent and the interest at state bank is 9 percent. How much should he invest in each bank to earn the most interest?
Answer provided by our tutors
let
c = the money invested in city bank
s = the money invested in state bank
Bob is planning to invest up to $25000 in city bank or state bank
c + s <= 25000
he wants to invest at least 3000 dollars n city bank, but not more than 23000 dollar
3000 <= c <= 23000
since state bank does not insure more than 7000 dollars, he wants to invest no more than this amount in state ban
s <= 7000
the interest at city bank is 7% and the interest at state bank is 9% thus the total interest will be
F(c, s) = 0.07c + 0.09s
we need to find c and s so that F(c, s) has maximum
from the graph of the system of inequalities (the constrains)
c + s <= 25000
3000 <= c
c <= 23000
s <= 7000
click here to see the graph
we find the corner points of the graph: (3000,0), (3000, 7000), (18000 ,7000), (23000, 2000) and (23000, 0)
the function F(c, s) = 0.07c + 0.09s takes its maximum at a corner point. we will calculate F(c, s) at each of the corner points:
F(3000,0) = 0.07*3000 = 210
F(3000, 7000) = 0.07*3000 + 0.09*7000 = 210 + 630 = 840
F(18000, 7000) = 0.07*18000 + 0.09*7000 = 1260 + 630 = 1890
F(23000, 2000) = 0.07*23000 + 0.09*2000 = 1610 + 180 = 1790
F(23000, 2000) = 0.07*23000 = 1510
for (18000, 7000) the function F has maximum thus Bob should invest $18,000 at the city bank and $7,000 at the state bank to earn most interest.