Problema Solution

Airplane A travels 2800 km at a certain speed. Plane B travels 2000 km at a speed 50 km/h faster than plan A in 3 hrs less time. Find the speed of each plane.

The speed of plane A is ______ km/hr.

The speed of plane B is _______ km/hr.

Answer provided by our tutors

let


d1 = 2800 km the distance plane A flies

d2 = 2000 km the distance plane B flies

v = the speed of plane A, v>0

v + 50 = the speed of plane B

t = the time of plane A

t - 3 = the time of plane B


since distance = speed*time


d1 = v*t


v*t = 2800 divid eboth sides by v


t = 2800/v


d2 = (v + 50)(t - 3)


(v + 50)(t - 3) = 2000


plug t = 2800/v into the last equation


(v + 50)(2800/v - 3) = 2000


by solving we find


v = 350 km/hr


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v + 50 = 350 + 50 = 400 km/hr


The speed of plane A is 350 km/hr.

The speed of plane B is 400 km/hr.