Problema Solution
if an object is propelled upward from ground level with an initial velocity of 75.2 feet per second, it's height h in feet t seconds later is given by the equation h=-16t^2+72.5t after how many seconds does the object hit the ground?
Answer provided by our tutors
h=-16t^2+72.5t
we need to find t such that h = 0 and t is not 0
-16t^2+72.5t = 0
by solving we find
t = 4.53125 s
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after 4.53125 s the object will hit the ground,