Problema Solution
The length of a rectangle is twice its width.
If the area of the rectangle is 50ft^2 , find its perimeter
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
the length of a rectangle is twice its width
l = 2w
the area of the rectangle is 50ft^2
l*w = 50
plug l=2w into l*w = 50
2w*w = 50
by solving we find
w = 5 ft
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l = 2*5
l = 10 ft
ther perimeter P = 2(l + w)
P = 2(5 + 10)
P = 30 ft
the perimeter is 30 ft.