Problema Solution
two planes which are 1490 miles apart fly towards each other. their speeds differ by 45 mph. if they pass each other in 2 hours, what is each of their speeds
Answer provided by our tutors
let
v = the speed of the first plane
v + 45 = the speed of the second plane
d = 1490 mi the distance between them
t = 2 hr the time of the flying
since speed = distance/time => distance = speed*time
v*t + (v + 45)*t = d
v*2 + (v + 45)*2 = 1490
by solving we find
v = 350 mph
click here to see the step by step solution of the equation
v + 45 = 350 + 45 = 395 mph
one plane is traveling with 350 mph and the other is traveling with 395 mph.