Problema Solution
A 7 pound bag of grass seed covers 6,000 square feet. How many pounds would be needed to cover 23,000 square feet?
Answer provided by our tutors
let x = lbs of seed needed to cover 23,000 ft^2
7 : 6000 = x : 23000
by solving we find
x = 26.83 lbs
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26.83 lbs of seed are needed to cover 23,000 ft^2.