Problema Solution
find three consecitive odd integers such that 4 times the sum of the last two is 2 greater than 10 times the first
Answer provided by our tutors
the three consecitive odd integers can be written as
2x-1, 2x+1, 2x+3
where x is integer
4 times the sum of the last two is 2 greater than 10 times the first
4(2x + 1 + 2x + 3) = 2 + 10(2x - 1)
by solving we find
x = 6
click here to see the step by step solution of the equation
2*6 - 1 = 11
2*6 + 1 = 13
2*6 + 3 = 15
the three consecitive odd integers are 11, 13 and 15.