Problema Solution

find the locus of the middle points of a system of parallel chords of the parabola y^2 = 4ax

Answer provided by our tutors

let the system of parallel chords have a slope m.


if (x1, y1) is the middle point of any one chord of this system then we wish to find the locus of (x1, y1).


Now equation of the chord with middle point (x1, y1) is


yy1 - 2a(x + x1) = y1^2 - 4ax1


slope of this chord = 2a/y1


but since we assumes that the slope is m we have


m = 2a/y1 or y1 = 2a/m


Hence locus of (x1, y1) is


y = 2a/m which is a line parallel to the axis of the parabola.