Problema Solution
A pizza shop offers twelve toppings.
How many different “six-topping pizzas”
can be formed with twelve toppings?
Answer provided by our tutors
C(12, 6) = 12!/((12 - 6)!*6!) = 12!/(6!*6!) = 7*8*9*10*11*12/(2*3*4*5*6) = 924 different “six-topping pizzas”