Problema Solution
A polygon with 4equal angles has a perimeter of 24x+56 all over 2.find its area.
Answer provided by our tutors
we will assume that the polygon is quadrilateral
since all 4 angles are equal follows the polygon is a rectangle
a = the length of the rectangle
b = the width of the rectangle
P = 2(a + b) is the perimeter and we know that P = (24x+56)/2 thus
2(a + b) = (24x+56)/2
a + b = 6x + 14
A = a*b is the area of the rectangle
A = a(6x + 14 - a)