Problema Solution
Khala paddeled for 4 hrs with a 6km current to a camp side.the return trip against the same current took 10 hrs. find the speed of Khala's canoe in stillwater
Answer provided by our tutors
let
v = the rate of the canoe in still water
c = the rate of the current
d = 6 km the distance traveled in one direction
t1 = 4 hr time of the travel downstream (with the current)
t2 = 10 hr the time of the return trip upstream (against the current)
the canoe's speed downstream: v + c
the canoe's speed upstream: v - c
since speed = distance/time => distance = speed*time
traveling downstream
(v + c)4 = 6
v + c = 6/4
traveling upstream
(v - c)10 = 6
v - c = 6/10
by solving the system of equations
v + c = 6/4
v - c = 6/10
we find
v = 1.05 km/hr
click here to see the step by step solution of the system of equations
the speed of Khala's canoe in still water is 1.05 km per hour.