Problema Solution
An object is thrown upward from the top of a 96 ft. building with a velocity of 80 feet per second. The height “h” of the object after “t” seconds is given by the quadratic equation h= -16t2+80t+96. When will the object hit the ground?
Answer provided by our tutors
let
t = the time it takes for the object to hit the ground, t >0
h= -16t^2+80t+96
the object will hit the ground when h = 0
by solving the quadratic equation
-16t^2+80t+96 = 0
we find and consider the positive root
t = 6 s
click here to see the step by step solution of the quadratic equation
the object will hit the ground after 6 seconds.