Problema Solution
Two people are carrying a box. One person exerts a force of 140 pounds at a angle of 65.5 with the horizontal. The other person exerts a force of 115 pounds at an angle of 58.3 with the horizontal. Find the net weight of the box.
Answer provided by our tutors
the vector for 40 pounds at 65.5 is: (140 cos(65.5) , 140 sin(65.5)) = (58.057 , 127.3946)
the vector for 115 pounds at 58.3° is: (115 cos (58.3) , 115 sin(58.3) = (60.429 , 96.9925)
lets add the two vectors to get the result:
(58.057 , 127.3946) + (60.429 , 96.9925) = (118.486 , 224.387)
magnitude (weight of the box) = √( sum of the squares of the components)
magnitude (weight of the box) = √(118.486^2 + 224.387^2)
magnitude (weight of the box) = 253.749 lbs