Problema Solution
The product of two consecutive integers is 11 less than the square of the smaller integer. Find the larger of the two integers.
The larger of the two integers is ____________.
Answer provided by our tutors
let 'x' represent the smaller integer, then 'x+1' represents the next consecutive integer
product of two consecutive integers is then: x(x+1)
the square of the smaller integer: x^2
adding 11 to the product gives us an expression equal to the square of the smaller integer, so we have this equation:
x(x+1) + 11 = x^2
solving for 'x' we have:
x=-11
-11+1 = -10
The larger of the two integers is -10