Problema Solution
the line passing through points (x,4) and (4,-5) is perpendicular to a line with a slope of -7/3 what is the value of x
Answer provided by our tutors
the slope of the line passing trough (x,4) and (4,-5) is m1 = (-5-4)/(4-x) = 9/(x-4)
the slope of the perpendicular line is m2 = -7/3
two line are perpendicular if the slopes are negative reciprocals or the product of the slopes is -1
m1*m2 = -1
(9/(x-4))*(-7/3) = -1
by solving we find
x = 25
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