Problema Solution
Find three consecutive positive integers such that the product of the first and third, minus the second, is one more than 4 times the third.
Answer provided by our tutors
The three consecutive positive integers can be written as
x-1, x and x+1,
where x-1>0 that is x>1 and x is integer
the product of the first and third, minus the second, is one more than 4 times the third
(x - 1)(x + 1) - x = 1 + 4(x + 1)
by solving we find
x = 6
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6 - 1 = 5
6 + 1 = 7
the number are 5, 6 and 7.