Problema Solution
A rocket is launched upward from a building at 1280 feet high with an initial velocity of 32 feet per second. The height, h, about ground level after t seconds is given by h=16t(squared)+32t+1280 where h is in feet. Find the maximum height.
Answer provided by our tutors
we need to find the maximum of the parabolic function
h(t) =16t^2+32t+1280
the maximum for f(x)= ax^2 + bx + c is given by the formula
f max = c - b^2/4a
thus in our case we have a = 16, b = 32 and c = 1280
h max = 1280 - 32^2/(4*16)
h max = 1264 ft
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the maximum height is 1254 feet.