Problema Solution
an object is thrown upward from the top of a 48-foot building with an initial velocity of 32 feet per second. The height h of the object after t seconds is given by the quadratic equation h=-32^2+32t+48. When will the object hit the ground?
Answer provided by our tutors
the object will hit the ground when h= 0 that is
-32^2+32t+48 = 0
by solving we find
t = 30.5 s
click here to see the step by step solution of the equation
the object will hit the ground after 30,5 seconds.