Problema Solution
how many ounces of a 5% alcohol solution must be mixed with 18 ounces of a 10% solution to make a 6% alcohol solution?
Answer provided by our tutors
let
x = oz on 5% alcohol solution
the new solution will be (x + 18) oz
0.05x + 0.10*18 = 0.06(x + 18)
by solving we find
x = 72 oz
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72 ounces of the 5% alcohol solution should be used for the mix.