All possible outcomes are

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

a) the probability of getting a total of 5

the displays that have total of 5 are:

(1,4)(2,3)(3,2)(4,1)

the probability = the number of displays that have total of 5 / the total number of displays

p = 4/36 = 1/9 = 0.1111

b) the probability of getting a two on black die and a six on white die

(2, 6)

and there is only 1 such display thus the probability is

p = 1/36 = 0.0278