Problema Solution
Sandy is 5 years older than his wife and his daughter is 5 times as his wife. If before 3 years the age of his daughter was 4 years. Then what is Sandy's today's age?
Answer provided by our tutors
let
s = Sandy's today's age
w = his wife's age
d = his daughter's age
Sandy is 5 years older than his wife
s = w + 5
his wife is 5 times as his daughter
w = 5d
before 3 years the age of his daughter was 4 years
d - 3 = 4
d = 4 + 3
d = 7
then w = 5*7 = 35 and finally s = 35 + 5 = 40.
Sandy is 40 years old now.