Problema Solution

Sandy is 5 years older than his wife and his daughter is 5 times as his wife. If before 3 years the age of his daughter was 4 years. Then what is Sandy's today's age?

Answer provided by our tutors

let


s = Sandy's today's age

w = his wife's age

d = his daughter's age


Sandy is 5 years older than his wife


s = w + 5


his wife is 5 times as his daughter


w = 5d


before 3 years the age of his daughter was 4 years


d - 3 = 4


d = 4 + 3


d = 7


then w = 5*7 = 35 and finally s = 35 + 5 = 40.


Sandy is 40 years old now.