Problema Solution
a newspaper carrier has 3.70 in change. He has five more quarters than dimes but five times as many nickels as quarters. how many coins of each type does he have?
Answer provided by our tutors
1 nickle = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
let
n = the number of nickels
d = the number of dimes
q = the number of quarters
a newspaper carrier has $3.70 = 370 cents in change
5n + 10d + 25q = 370 divide both sides by 5
n + 2d + 5q = 74
he has five more quarters than dimes
q = 5 + d
and five times as many nickels as quarters
n = 5q
by solving the system of equations
n + 2d + 5q = 74
q = 5 + d
n = 5q
we find
n = 35 nickles
d = 2 dimes
q = 7 quarters
click here to see the step by step solution of the system of equations
there are 35 nickles, 2 dimes and 7 quarters.