Problema Solution
if a baseball is projected upward from ground level with an initial velocity of 160 feet per second, then its height is a function of time, given by s=-16t^2 + 160t.
what is the maximum height reached by the ball?
Answer provided by our tutors
s=-16t^2 + 160t
we need to find the maximum value of the parabolic function s=-16t^2 + 160t
s max = c - b^2/(4a) where a = -16, b = 160, c = 0
s max = 0 - 160^2/(4*(-16))
s max = 400 ft
click here to see the step by step solution of the equation
the maximum height reached by the ball is 400 feet.