Problema Solution
a chemist wants to mix a 65% alcohol solution with 6 liter of a 49% alcohol solution to produce a solution that is 58% alcohol. how many liters of the 65% solution should be used?
Answer provided by our tutors
let
x = l of the 65% alcohol solution
y = 6 l of 49% alcohol solution
x + y = the mix is 58 alcohol solution
0.60x + 0.49*y = 0.50*(x + 6)
0.60x + 0.49*6 = 0.50*(x + 6)
by solving we find
x = 27 l
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27 liters of the 60% colution should be used.