Problema Solution
a newspaper carrier has $4.00 in change. He has four more quarters than dimes but four times as many nickels as quarters.How many coins of each type does he have?
Answer provided by our tutors
1 nickle = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
let
n = the number of nickels
d = the number of dimes
q = the number of quarters
a newspaper carrier has $4.70 = 400 cents in change
5n + 10d + 25q = 400 divide both sides by 5
n + 2d + 5q = 80
he has four more quarters than dimes
q = 4 + d
and four times as many nickels as quarters
n = 4q
by solving the system of equations
n + 2d + 5q = 80
q = 4 + d
n = 4q
we find
n = 32 nickles
d = 4 dimes
q = 8 quarters
click here to see the step by step solution of the system of equations
he has 32 nickles, 4 dimes and 8 quarters.