Problema Solution
What quantity of a 50% acid solution just be mixed with a 20% solution to produce 300mL of a 40% solution?
Answer provided by our tutors
let
x = mL of a 50% acid solution
y = mL of a 20% acid solution
x + y = 300
the % of acid in x + the % of acid in y = 40% acid in 300 mL
0.50x + 0.20y = 0.40*300
by solving the system of equations
x + y = 300
0.50x + 0.20y = 0.40*300
we find
x = 200 mL
y = 100 mL
click here to see the step by step solution of the system of equations
200 mL of 50% acid solution should be mixed with 100 mL of 20% acid solution.