Problema Solution
Find the sum of 18 terms of the gp 3,6,12
Answer provided by our tutors
To find the sum of the first n terms of a geometric sequence use the formula
Sn = a1(1 - r^n)/(1 - r)
where n is the number of terms, a1 is the first term and r is the common ratio.
In our case n = 18, a1 = 3, r = 2
S18 = 3(1 - 2^18)/(1 - 2)
S18 = 786,429
the sum of the first 18 terms of the gp is 786,429.