Problema Solution
One type of gashole is 10% alcohol and another type is 35% percent alcohol. How much of each type must be mixed to obtain 400 gallons does a 25% mixture
Answer provided by our tutors
let
x = gal of the 10% alcohol type
y = gal of the 35% alcohol type
the obtained mix is 400 gal and has 25% alcohol
x + y = 400
0.10x + 0.35y = 0.25*400
by solving the above system of equations we find
x = 160 gal
y = 240 gal
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160 gal of the 10% alcohol type should be mixed with 240 gal of the 35% alcohol type.