Problema Solution
Tank A contains 50 liters of a 25% sulfuric acid solution. Tank B contains 50 liters of a 40% sulfuric acid solution. how many liters from each tank must be mixed to produce 30 liters of a 30% solution.
Answer provided by our tutors
let
a = liters from tank A needed for the mix
a <= 50
b = liters from tank B needed for the mix
b <= 40
the mix is 30 liters of a 30% solution
a + b = 30
0.25a + 0.40b = 0.30*30
by solving the above system of equations we find
a = 20 l
b = 10 l
click here to see the step by step solution of the system of equations
20 liters of the 25% sulfuric acid solution and 10 liters of the 40% sulfuric acid solution should be used for the mix.